Toothpaste?

The lethal dose of fluoride is estimated to be 75 mg F- per kilogram body mass for humans. How many tubes of toothpaste would a 70kg adult have to consume to reach this level? A typical tube holds x g of toothpaste containing 0.24% w/w of sodium flouride

Toothpaste?
In terms of X?





75 mg/kg * 70 kg = 5250 mg of fluoride.





If the toothpaste was 0.24% w/w fluoride then





5250 mg / 0.0024 = 2187500 mg of toothpaste





= 2187.5 grams (this is like 4.8 pounds!!)





2187.5 grams toothpaste / X grams per tube = number of tubes
Reply:ghdddddhhhhhhhhhhhhhhhhhhhhh
Reply:actually spkin....


fluorine reqd is so low dat...it cud b estimated to be negligible..


but if u really wana calculate....give me a day or two
Reply:it would depend on the size and weight of the person ingesting the toothpaste.. it would be a good question for mythbusters
Reply:Multiply 75 X 70 to see the total dose. Multiply x by 1000 to convert to milligrams, then by 0.0024 to see how many mg of fluoride in each tube. Divide your first answer by this last answer to see how many tubes.
Reply:Ok, Na = 23.0 g/mol, F = 19.0 g/mol so a 100 gram tube of toothpaste should have (19.0/(23.0+19.0))x100g x (0.24%/100%) = 0.1086 g of F or 108.6 mg of F. Lethal dose (LD) = 75 mg/Kg x 70 Kg = 5250 mg of F is lethal to a 70 Kg adult. So 5250 mg / 108.6 mg/ 100g tube = 48.34 100 g tubes or rounded up 49 100 g tubes of tooth paste would be fatal! Hope this all makes sense. :-)
Reply:Alright, you TSA employee, stop eating people%26#039;s toothpaste and get back to work.
Reply:For a 70 kg adult,lethal dose of fluoride = (70*75)mg=5250mg=5.25g .


Let us suppose that n tubes would work out the problem,so,


n*x*24/10000=5.25


n = 52500/(x*24)


n = 2187.5/x